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Girder with Uniform Load.                  441

A.        /W    7\       /W     /\                7

AtB=f~xr)   -f_.X-M     ^w/x-^-     oc    7

128            '

At c-f-^-xM   /:L._M     _ur/., 3

AtD-(*x|/WlWx4/Uw/x-!L

OC    12

32

\2     8V     V" "i6V            128     "  ^

AtE = (7xO  ~GH)     = w/* I     - i

and are  similarly found between H and E, all being shewn on
base ad.    Drawing/^-horizontally, the intercepts between kf
and tf/are seen to vary as in Fig. 395, and the. curve is therefore
a parabola with vertex at/

The Shearing Force is found by deducting upward and down-
ward forces on the right of each section.    Thus :

W

At
	A
	= W-
	1 _
	Wx
	X
	oc
	4


	
	
	2
	
	2
	
	

At
	B
	-}w-
	W
 2   ~~
	Wx
	3 8
	OC
	3


	
	3
	W
	
	i
	
	

At
	C
	= ^w~
	
	Wx
	
	OC
	2


	
	4
	2   ~"
	
	4
	
	

At
	D
	= ~W~
	W
	Wx
	i
	OC
	I


	
	8
	2
	
	8
	
	

At
	E
	W
	W
	0
	
	OC
	0


	
	2
	2
	
	
	
	

Ate-      ---

4      2.                4

-Wx|      OC-;
8

A.t J =       -IL==:^VVx-cx-4

2                      2

There is no force whatever at the centre,                     '..,./,.

VI. Beam fixed at both ends andloafad in the centre (Fig. 399}?.
weight of beam neglected. The beam will be deflected to the
dotted shape, A c and & j acting as cantilevers, and c G as a
supported girder. From c to G the Bm is upward, and from'1*